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	<title>Comments on: Pissed off nerd writes a check using a formula as the amount</title>
	<link>http://www.sledgehammertotheface.com/2008/05/23/pissed-off-nerd-writes-a-check-using-a-formula-as-the-amount/</link>
	<description>Because the asshole deserved it!</description>
	<pubDate>Thu, 08 Jan 2009 20:53:02 +0000</pubDate>
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		<title>By: Robert</title>
		<link>http://www.sledgehammertotheface.com/2008/05/23/pissed-off-nerd-writes-a-check-using-a-formula-as-the-amount/#comment-877</link>
		<dc:creator>Robert</dc:creator>
		<pubDate>Fri, 30 May 2008 06:13:23 +0000</pubDate>
		<guid>http://www.sledgehammertotheface.com/2008/05/23/pissed-off-nerd-writes-a-check-using-a-formula-as-the-amount/#comment-877</guid>
		<description>"the proof is technical, but e^pi*i=-1, therefore
0.002 + -1 + 1 = 0.002 = 0.2 cents."

No it is not. Maybe for a highschool dropout.

Euler's Formula:
e^ix = cosx + i*sinx

Therefor:
e^(i*pi) = cos(pi) + i*sin(pi)
e^(i*pi) = -1 + i * 0
e^(i*pi) = -1</description>
		<content:encoded><![CDATA[<p>&#8220;the proof is technical, but e^pi*i=-1, therefore<br />
0.002 + -1 + 1 = 0.002 = 0.2 cents.&#8221;</p>
<p>No it is not. Maybe for a highschool dropout.</p>
<p>Euler&#8217;s Formula:<br />
e^ix = cosx + i*sinx</p>
<p>Therefor:<br />
e^(i*pi) = cos(pi) + i*sin(pi)<br />
e^(i*pi) = -1 + i * 0<br />
e^(i*pi) = -1</p>
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		<title>By: Vijay Santhanam</title>
		<link>http://www.sledgehammertotheface.com/2008/05/23/pissed-off-nerd-writes-a-check-using-a-formula-as-the-amount/#comment-868</link>
		<dc:creator>Vijay Santhanam</dc:creator>
		<pubDate>Sat, 24 May 2008 15:17:10 +0000</pubDate>
		<guid>http://www.sledgehammertotheface.com/2008/05/23/pissed-off-nerd-writes-a-check-using-a-formula-as-the-amount/#comment-868</guid>
		<description>Also, the first symbols are e^ pi * i, where i = sqrt(-1).

the proof is technical, but e^pi*i=-1, therefore 
0.002 + -1 + 1 = 0.002 = 0.2 cents.

XKCD appeals to the obsessive math/programming nerd within.</description>
		<content:encoded><![CDATA[<p>Also, the first symbols are e^ pi * i, where i = sqrt(-1).</p>
<p>the proof is technical, but e^pi*i=-1, therefore<br />
0.002 + -1 + 1 = 0.002 = 0.2 cents.</p>
<p>XKCD appeals to the obsessive math/programming nerd within.</p>
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		<title>By: chris</title>
		<link>http://www.sledgehammertotheface.com/2008/05/23/pissed-off-nerd-writes-a-check-using-a-formula-as-the-amount/#comment-863</link>
		<dc:creator>chris</dc:creator>
		<pubDate>Fri, 23 May 2008 14:24:23 +0000</pubDate>
		<guid>http://www.sledgehammertotheface.com/2008/05/23/pissed-off-nerd-writes-a-check-using-a-formula-as-the-amount/#comment-863</guid>
		<description>Thanks for pointing out that I'm an ass wipe that believes everything he sees ;)</description>
		<content:encoded><![CDATA[<p>Thanks for pointing out that I&#8217;m an ass wipe that believes everything he sees <img src='http://www.sledgehammertotheface.com/wp-includes/images/smilies/icon_wink.gif' alt=';)' class='wp-smiley' /></p>
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		<title>By: Rex</title>
		<link>http://www.sledgehammertotheface.com/2008/05/23/pissed-off-nerd-writes-a-check-using-a-formula-as-the-amount/#comment-862</link>
		<dc:creator>Rex</dc:creator>
		<pubDate>Fri, 23 May 2008 14:14:07 +0000</pubDate>
		<guid>http://www.sledgehammertotheface.com/2008/05/23/pissed-off-nerd-writes-a-check-using-a-formula-as-the-amount/#comment-862</guid>
		<description>I'm guessing not Brian.</description>
		<content:encoded><![CDATA[<p>I&#8217;m guessing not Brian.</p>
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		<title>By: Brian</title>
		<link>http://www.sledgehammertotheface.com/2008/05/23/pissed-off-nerd-writes-a-check-using-a-formula-as-the-amount/#comment-861</link>
		<dc:creator>Brian</dc:creator>
		<pubDate>Fri, 23 May 2008 13:54:53 +0000</pubDate>
		<guid>http://www.sledgehammertotheface.com/2008/05/23/pissed-off-nerd-writes-a-check-using-a-formula-as-the-amount/#comment-861</guid>
		<description>um...you realize that it's the guy that creates the uber-popular XKCD web comic, right?</description>
		<content:encoded><![CDATA[<p>um&#8230;you realize that it&#8217;s the guy that creates the uber-popular XKCD web comic, right?</p>
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